NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1.

- Practical Geometry Class 8 Ex 4.2
- Practical Geometry Class 8 Ex 4.3
- Practical Geometry Class 8 Ex 4.4
- Practical Geometry Class 8 Ex 4.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 4.1 |

Number of Questions Solved |
1 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 4 Practical Geometry Ex 4.1

**Question 1.**

**Construct the following quadrilaterals:**

**(i)** **Quadrilateral ABCD**

AB = 4.5 cm

BC = 5.5 cm

CD = 4 cm

AD = 6 cm

AC = 7 cm

**(ii)** **Quadrilateral JUMP**

JU = 3.5 cm

UM = 4 cm

MP = 5 cm

PJ = 4.5 cm

PU 6.5 cm

**(iii)** **Parallelogram MORE**

OR = 6 cm

RE = 4.5 cm

EO = 7.5 cm

**(iv) Rhombus BEST**

BE = 4.5 cm

ET = 6 cm

**Solution.**

**(i) Steps of Construction**

- Draw AB 4.5 cm
- With A as centre and radius AC = 7 cm, draw an arc.

- With B as center and radius BC = 5.5 cm, draw another arc to intersect the arc drawn in step (2) at C.
- With A as center and radius AD = 6 cm, draw an arc on the side of AC, opposite to that of B.
- With C as center and radius CD = 4 cm, draw another arc to intersect the arc drawn in step (4) at D.
- Join BC, CD, DA, and AC.

Then, ABCD is the required quadrilateral.

**(ii) Steps of Construction**

- Draw JU = 3.5 cm
- With J as center and radius JP = 4.5 cm, draw an arc.
- With U as center and radius UP = 6.5 cm, draw another arc to intersect the arc drawn in step 2 at P.

- With U as center and radius UM = 4 cm, draw an arc on the side of PU opposite to that of J.
- With P as center and radius PM = 5 cm, draw another arc to intersect the arc drawn in step 4 at M.
- Join UM, MP, PJ, and UP.

Then, JUMP is the required quadrilateral.

**(iii) Steps of Construction**

[We know that in a parallelogram, opposite sides are equal in length.

∴ MO = ER = 4.5 cm and ME – OR = 6 cm]

- Draw MO = 4.5 cm
- With M as center and radius ME = 6 cm, draw an arc.

- With O as center and radius OE = 7.5 cm, draw an arc to intersect the arc drawn in step 2 at E.
- With O as center and radius OR = 6 cm, draw an arc on the side of OE opposite to that of M.
- With E as center and radius ER = 4.5 cm, draw another arc to intersect the arc drawn in step 4 at R.
- Join OR, RE, EM, and EO.

Then, MORE is the required parallelogram.

**(iv) Steps of Construction**

[We know that in a rhombus, all the sides are equal in length.

∴ BE = ES = ST = TB = 4.5 cm]

- Draw BE = 4.5 cm
- With B as centre and radius BT = 4.5 cm, draw an arc.

- With E as center and radius

ET = 6 cm, draw another arc to intersect the arc drawn in step 2 at T. - With E as center and radius

ES = 4.5 cm, draw an arc on the side of ET opposite to that of B. - With T as center and radius

TS = 4.5 cm, draw another arc to

intersect the arc drawn in step 4 at S. - Join ES, ST, TB, and TE.

Then, BEST is the required rhombus.

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