## RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.3

These Solutions are part of RD Sharma Class 8 Solutions. Here we have given RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.3

**Other Exercises**

- RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.1
- RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.2
- RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.3

**Solve each of the following cryptarithms.**

**Question 1.**

**Solution:**

Values of A and B be from 0 to 9 In ten’s digit 3 + A = 9

∴ A = 6 or less.

∴ 7 + B = A = 6 or less

∴ 7 + 9 or 8 = 16 or 15

∴ But it is two digit number

B = 8

Then A = 5

**Question 2.**

**Solution:**

Values of A and B can be between 0 and 9

In tens digit, A + 3 = 9

∴ A = 9 – 3 = 6 or less than 6

In ones unit B + 7 = A = 6or less

∴ 7 + 9 or 8 = 16 or 15

But it is two digit number

∴ B = 8 and

∴ A = 5

**Question 3.**

**Solution:**

Value of A and B can be between 0 and 9 In units place.

1+B = 0 ⇒1+B = 10

∴ B = 10 – 1 = 9

and in tens place

1 + A + 1 = B ⇒ A + 2 = 9

⇒ A = 9 – 2 = 7

**Question 4.**

**Solution:**

Values of A and.B can be between 0 and 9

In units place, B+1 = 8 ⇒ B = 8-1=7

In tens place A + B= 1 or A + B = 11

⇒ A + 7 = 11 ⇒ A =11-7 = 4

**Question 5.**

**Solution:**

Values of A and B can be between 0 and 9

In tens place, 2 + A = 0 or 2 + A=10

A = 10-2 = 8

In units place, A + B = 9

⇒ 8 + B = 9 ⇒ B = 9- 8 = 1

**Question 6.**

**Solution:**

Values of A and B can be between 0 and 9

In hundreds place,

**Question 7.**

**Show that cryptarithm 4 x \(\overline { AB } =\overline { CAB }\) does not have any solution.**

**Solution:**

It means that 4 x B is a numebr whose units digit is B

Clearly, there is no such digit

Hence the given cryptarithm has no solution.

Hope given RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.3 are helpful to complete your math homework.

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