## RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.1

These Solutions are part of RD Sharma Class 8 Solutions. Here we have given RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.1

**Other Exercises**

- RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.1
- RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.2
- RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.3

**Question 1.**

**Without performing actual addition and division, write the quotient when the sum of 69 and 96. is divided by**

**(i) 11 **

**(ii) 15**

**Solution:**

Two numbers are 69 and 96 whose digits are reversed Here a = 6,= 9

(i) Sum if 69 + 96 is divisible by 11, then quotient = a + 6 = 6 + 9 = 15

(ii) If it is divided by a + b i.e., 6 + 9 = 15, then quotient = 11

**Question 2.**

**Without performing actual computations, find the quotient when 94 – 49 is divided by**

**(i) 9**

** (ii) 5**

**Solution:**

Two given numbers are 94 and 49. Whose digits are reversed.

(i) If 94 – 49 is divided by 9, then the quotient = a-b = 9-4 = 5

(ii) and when it is divided by a – b i.e. 9-4 = 5, then quotient will be = 9

**Question 3.
**

**If sum of the number 985 and two other numbers obtained by arranging the digits of 985 in cyclic order is divided by 111, 22**

**and 37 respectively. Find the quotient in each case.**

**Solution:**

The given number is 985

The other two numbers by arranging its digits

in cyclic order, will be 859, 598 of the form

\(\overline{ abc } ,\overline{ bca } ,\overline{ cba }\)

Therefore,

If 985 + 859 + 598 is divided by 111, then quotient will bea + 6 + c = 9 + 8 + 5 = 22

If this sum is divided by 22, then the quotient = 111

and if it is divided by 37, then quotient = 3 (a + b + c) = 3 (22) = 66

**Question 4.**

**Find the quotient when difference of 985 and 958 is divided by 9.**

**Solution:**

The numbers of three digits are

985 and 958 in which tens and ones digits are reversed, then

\(\overline{ abc } -\overline{ acb }\) = 9 (b – c)

985 – 958 = 9 (8 – 5) = 9 x 3

i. e., it is divisible by 9, then quotient = b-c =8-5=3

Hope given RD Sharma Class 8 Solutions Chapter 5 Playing With Numbers Ex 5.1 are helpful to complete your math homework.

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