NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Quadratic Equations |

Exercise |
Ex 4.2 |

Number of Questions Solved |
6 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2

**Ex 4.2 Class 10 NCERT Solutions Question 1.**

**Find the roots of the following quadratic equations by factorisation:**

**(i) x ^{2} -3x – 10 = 0**

**(ii) 2x**

^{2}+ x – 6 = 0**(iii) √2x**

^{2}+ 7x + 5√2 = 0**(iv) 2x**

^{2}– x + \(\frac { 1 }{ 8 }\) = 0 8**(v) 100 x**

^{2}– 20 X + 1 = 0**Solution:**

**Class 10 Maths 4.2 NCERT Solutions Question 2.
**

**Solve the following situations mathematically:**

**(i)** John and Jivanti together have 45 marbles. Both of them lost 5 marbles each and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.

**(ii)** A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was ₹750. We would like to find out the number of toys produced on that day.

**Solution:
**

**(i)**Let the number of marbles John had be x

Then, the number of marbles Jivanti had = 45 -x

The number of marbles left with John, when he lost 5 marbles = x – 5

The number of marbles left with Jivanti, when she lost 5 marbles = 45 -x – 5 = 40 -x

**Ex 4.2 Class 10 Question 3.
**

**Find two numbers whose sum is 27 and product is 182.**

**Solution:**

Let one number = x ,

∴ other number = 21 -x

According to question,

**Question 4.
**

**Find two consecutive positive integers, sum of whose squares is 365.**

**Solution:**

Let the two consecutive integers be x and x + 1.

According to question,

**Ex 4.2 Class 10 Question 5.
**

**The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.**

**Solution:**

Let base = x cm,

∴ height = (x – 7) cm

By Pythagoras Theorem,

(base)² + (height)² = (hypotenuse)²

**Ex 4.2 Class 10 Question 6.
**

**A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was ₹90, find the number of articles produced and the cost of each article.**

**Solution:**

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