## RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.4

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.4

**Other Exercises**

- RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.1
- RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.2
- RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.3
- RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.4
- RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry VSAQS
- RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry MCQS

**Question 1.
**

**Give the geometric representations of the following equations.**

**(a) on the number line**

**(b) on the cartesian plane.**

**(i) x – 2**

**(ii) y + 3 = 0**

**(iii) y = 3**

**(iv) 2x + 9 = 0**

**(v) 3x – 5 = 0**

**Solution:**

(i) x = 2

(i) on the number line

(ii) x = 2 is a line parallel to 7-axis at a distance of 2 units to right of y-axis.

(ii) y = -3 is a line parallel to x-axis at a distance of 3 units below x-axis.

(iii) y = 3

(i) y = 3

(ii) y = 3 is a line parallel to x-axis at a distance of 3 units above x-axis.

x = -4.5 is a line parallel to 7-axis at a distance of 4.5 units to left of y-axis.

(ii) x = 1\(\frac { 2 }{ 3 }\) is a line parallel to y-axis at a distance of 1\(\frac { 2 }{ 3 }\) unit to right side of y-axis.

**Question 2.
**

**Give the geometrical representation of 2x + 13 = 0 as an equation in**

**(i) One variable**

**(ii) Two variables**

**Solution:**

(i) In one variable,

2x + 13 = 0

⇒ 2x = – 13

⇒ x = \(\frac { -13 }{ 2 }\)

is a line parallel to y-axis at a distance of -6 \(\frac { 1 }{ 2 }\) units on the left side of y-axis.

**Question 3.
**

**Solve the equation 3x + 2 = x -8, and represent on**

**(i) the number line**

**(ii) the Cartesian plane.**

**Solution:**

3x + 2 = x – 8

⇒ 3x – x = -8 – 2

⇒ 2x = -10

⇒ x = \(\frac { -10 }{ 2 }\) = -5

(i) on the number line s = -5

(ii) x = -5 is a line parallel to y-axis at a distance of 5 knot’s left of y-axis.

**Question 4.
**

**Write the equal of the line that is parallel to x-axis and passing through the points.**

**(i) (0, 3)**

**(ii) (0, -4)**

**(iii) (2, -5)**

**(iv) (3, 4)**

**Solution:**

∵ A line parallel to x-axis will be of the type y = a

∴ (i) y = 3

(ii) y = -4

(iii) y = -5 and y = 4 are equations of the lines parallel to x-axis

**Question 5.
**

**Write the equation of the line that is parallel to y-axis and passing through the points.**

**(i) (4, 0)**

**(ii) (-2, 0)**

**(iii) (3, 5)**

**(iv) (-4, -3)**

**Solution:**

∵ A line parallel to y-axis will be of the type x = a

∴ (i) x = 4, (ii) x = -2, x = 3 and x = -4 are the equations of the lines parallel to y-axis.

Hope given RD Sharma Class 9 Solutions Chapter 7 Introduction to Euclid’s Geometry Ex 7.4 are helpful to complete your math homework.

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