NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4.

- Practical Geometry Class 6 Ex 14.1
- Practical Geometry Class 6 Ex 14.2
- Practical Geometry Class 6 Ex 14.3
- Practical Geometry Class 6 Ex 14.5
- Practical Geometry Class 6 Ex 14.6

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 14.4 |

Number of Questions Solved |
3 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4

Question 1.

Draw any line segment \(\overline { AB }\) . Mark any point M on it. Through M draw a perpendicular to \(\overline { AB }\). (use ruler and compasses).

Solution :

**Step 1.** Given a point M on any line \(\overline { AB }\).

**Step 2.** With M as centre and a convenient radius, construct a part circle (arc) intersecting the line segment \(\overline { AB }\) at two points C and D.

**Step 3.** With C and D as centres and a radius greater than CM, construct two arcs which cut each other at N.

**Step 4.** Join \(\overline { MN }\). Then \(\overline { MN }\) is perpendicular to \(\overline { AB }\) at M, i.e., \(\overline { MN }\) \(\overline { AB }\).

Question 2.

Draw any’line segment \(\overline { PQ }\). Take any point R not on it. Through R draw a perpendicular to \(\overline { PQ }\). (use ruler and set-square).

Solution :

**Step 1.** Let \(\overline { PQ }\) be the given line segment and R be a point not on it.

**Step 2.** Place a set-square on \(\overline { PQ }\) such that one arm of the right angle aligns along \(\overline { PQ }\).

**Step 3.** Place a ruler along the edge opposite of the right angle.

**Step 4.** Hold the ruler fixed. Slide the set-square along the ruler all the point R touches the arm of the set-square.

**Step 5.** Join RS along the edge through R, meeting \(\overline { PQ }\) at S. Now \(\overline { RS }\) \(\overline { PQ }\).

Question 3.

Draw a line l and a point X on it. Through X, draw a line segment \(\overline { XY }\) perpendicular to l. Now draw a perpendicular to XY at Y. (use ruler and compasses)

Solution :

**Step 1.** Given a point X on a line l.

**Step 2.** With X as centre and a convenient radius, construct a part circle (arc) intersecting the line l at two points A and B.

**Step 3.** With A and B as centres and a radius greater than AX, construct two arcs which cut each other at Y.

**Step 4.** Join \(\overline { XY }\). Then \(\overline { XY }\) is perpendicular to l atX, i.e., \(\overline { XY }\) l.

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