Check the below NCERT MCQ Questions for Class 12 Chemistry Chapter 13 Amines with Answers Pdf free download. MCQ Questions for Class 12 Chemistry with Answers were prepared based on the latest exam pattern. We have provided Amines Class 12 Chemistry MCQs Questions with Answers to help students understand the concept very well.
Amines Class 12 MCQs Questions with Answers
Nitrogen atom of amino group is ………. hybridised.
Answer: (c) sp3
Which of the following should be most volatile?
Answer: (b) IV
C3H8N cannot represent
(a) 1° ammine
(b) 2° ammine
(c) 3° ammine
(d) quartemary ammonium salt
Answer: (d) quartemary ammonium salt
Identify the correct IUPAC name
(a) (CH3CH2)2NCH3 = N-Ethyl-N-methylethanamine
(b) (CH3)3CNH2 = 2-methylpropan-2-amine
(c) CH3NHCH (CH3)2 = N-Methylpropan-2-amine
(d) (CH3)2CHNH2 = 2, 2-Dimethyl-N-propanamine
Answer: (a) (CH3CH2)2NCH3 = N-Ethyl-N-methylethanamine
The most convenient method to prepare primary (i Amine) amine containing one carbon atom less is
(a) Gabriel phthalmidie synthesis
(b) Reductive amination of aldehydes
(c) Hofmann bromamide reaction
(d) Reduction of isonitriles
Answer: (c) Hofmann bromamide reaction
Identify the correct pathway to convert propanoic acid to ethylamine. The reagent represented by A, B and C are
When excess of ethyl iodide is treated with ammonia, the product is
(d) tetrathylammonium iodide
Answer: (d) tetrathylammonium iodide
Amides may be converted into amines by a reaction named after
(a) Hofmann Bromide
Answer: (a) Hofmann Bromide
Reduction of CH3CH2NC with hydrogen in presence of Ni or Pt as catalvst gives
Answer: (b) CH3CH2NHCH3
Secondary amines can be prepared by
(a) reduction of nitro compounds
(b) oxidation of N-substituted amides
(c) reduction of isonitriles
(d) reduction of nitriles
Answer: (c) reduction of isonitriles
Which of the following amides will give ethylamine on reaction with sodium hypobromide?
Answer: (b) Propanamide
Benzoic acid is treated with SOCl2 and the product (X) formed is reacted with ammonia to give (Y). (Y) on reaction with Br2 and KOH gives (Z). (Z) in the reaction is
(d) benzoyl chloride
Answer: (a) aniline
Which one of the following reducing agents is likely to be most effective in bringing about the following change?
(c) LiAlH4 ether
Answer: (c) LiAlH4 ether
Amine that cannot be prepared by Gabricl-Phthalmidie synthesis is
(b) benzyl amine
(c) methyl amine
Answer: (a) aniline
What is the end product in the following sequence of reactions?
(d) Benzenediazxonium chloride
Answer: (a) Aniline
Tertiary amines have lowest boiling points amongst isomeric amines because
(a) they have highest molecular mass
(b) they do not form hydrogen bonds
(c) they are more polar in nature
(d) they are most basic in nature
Answer: (b) they do not form hydrogen bonds
Which of the following amines will give carbylatnine reaction?
Answer: (c) C2H5NH2
in the above reaction is
Answer: (a) CH3CH2CH2NHCOCH3
The end product Z of the reaction
Answer: (a) propanenitrile
Primary and secondary amines are distinguished by
Answer: (c) HNO2
Arrange the following compounds in increasing order of basicity:
CH3NH2, (CH3)2 NH, NH3, C6H5NH2
(a) C6H5NH2 < NH3 < (CH3)2NH < CH3NH2
(b) CH3NH2 < (CH3)2NH < NH3 < C6H5NH2
(c) C6H5NH2 <NH3 < CH3NH2<(CH3)2NH
(d) (CH3)2NH < CH3NH2 <NH3 < C6H5NH2
Answer: (c) C6H5NH2 <NH3 < CH3NH2<(CH3)2NH
Which of the following species are involved in the carbvlamine test?
(iv) NaNO2 + HCl
(a) (i) and (iv)
(b) (i) and (ii)
(c) (ii) and (iv)
(d) (ii) and (iii)
Answer: (b) (i) and (ii)
Identify ‘Z’ in the sequence?
Answer: (c) C6H5COOH
Which of the following from isocyanide on reaction with CHCl and KOH?
(d) C6H5N (C2H5)2
Answer: (b) CH3C6H4NH2
Which of the following is used as Hinsberg’s reagent?
Answer: (a) C6H5SO2Cl
Electrophilic substitution of aniline with bromine water at room temperature gives
(c) 2, 4, 6-tribromoaniline
(d) 3, 5, 6-tribromoaniline
Answer: (c) 2, 4, 6-tribromoaniline
Among the compounds C3H7NH2, CH3NH2, C2H5NH2, and C6H5NH2. Which is the least basic compound?
Answer: (d) C6H5NH2
Anilinium hydrogensulphate on heating with sulphuric acid at 453-473 K produces
(a) sulphanilic acia
(b) benzenesulphonic acid
(d) anthranilic acid
Answer: (a) sulphanilic acia
Product would be
Which of the following can exist as zwitter ion?
(b) Sulphanilic acid
Answer: (b) Sulphanilic acid
Reduction of aromatic nitro-compounds using Sn and HCl gives
(a) aromatic primary amines
(b) aromatic secondary amines
(c) aromatic tertiary amines
(d) aromatic amides
Answer: (a) aromatic primary amines
Which amine amongst the following will answer positively the carbylamine test (i.e., heating with CHCl3 and KOH)?
(a) C6H5 – NH – CH3
(c) C6H5 – NH – C4H9
(d) C6H5 -N(C2H5)3
Most basic species amongst the following is
When aniline is heated with cone. H2SO4 at 455-475 K, it forms
(a) aniline hydrogensulphate
(b) sulphanilic acid
(c) amino benzene sulphonic acid
(d) benzenesulphonic acid
Answer: (b) sulphanilic acid
Which of the following compounds cannot be identified by carbylamine test?
Answer: (d) C6H5NHC6H5
What is obtained when benzoyl chloride reacts with aniline in the presence of sodium hydroxide?
(a) Benzoic acid
Answer: (b) Benzanilide
Which of the following compounds reacts with NaNO2 and HCl at 0-4°C to give alcohol/phenol?
Answer: (b) C2H5NH2
Which of the following has highest pKb value?
Answer: (b) NH3
Acetylation of a secondary amine in alkaline medium yields
(a) N, N-dialkyl acetamide
(b) N, N-dialkyl amine
(c) N, N-dialkyl amide
(d) acetyl dialkyl amine
Answer: (a) N, N-dialkyl acetamide
Which of the following is amphoteric in nature?
Answer: (c) CH3CONH2
The amines are basic in nature, hence they form salts with hydrochloric acid. Which of the following will be insoluble in dil. HCl?
Answer: (b) (C6H5)3N
Primary, secondary and tertiary amines may be separated by using
(c) benzene sulphonyl chloride
(d) acetyl chloride
Answer: (c) benzene sulphonyl chloride
When p-toluidine reacts with chloroform and alcoholic KOH, then the product is
An organic compound (X) was treated with sodium nitrite and HCl in ice cold conditions. Bubbles of nitrogen gas were seen coming out. The compound (X) may be
(a) a secondary aliphatic amine.
(b) a primary aromatic amine
(c) a primary aliphatic amine
(d) a tertiary amine
Answer: (c) a primary aliphatic amine
Among the following:
Which will give the positive carbylamine test?
(a) I and II
(b) I and IV
(c) II and IV
(d) II and III
Answer: (b) I and IV
Cyclohexyiamine is stronger base than aniline become
(a) in aniline electron pair is involved in conjugation
(b) in cyclohexyiamine electron pair is involve conjugation
(c) in aniline-NH, group is protonated
(d) in cyclohexyiamine nitrogen has a negative charge
Answer: (a) in aniline electron pair is involved in conjugation
The strongest base among the following is
Answer: (d) C6H5CH2NH2
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