NCERT Solutions for Class 7 Science Chapter 13 Motion and Time are part of NCERT Solutions for Class 7 Science. Here we have given NCERT Solutions for Class 7 Science Chapter 13 Motion and Time.
|Chapter Name||Motion and Time|
|Number of Questions Solved||13|
NCERT Solutions for Class 7 Science Chapter 13 Motion and Time
Classify the following as motion along a straight line, circular or oscillatory motion:
(i) Motion of your hands while running.
(ii) Motion of a horse pulling a cart on a straight road.
(iii) Motion of a child in a merry-go-round.
(iv) Motion of a child on a see-saw.
(v) Motion of the hammer of an electric bell.
(vi) Motion of a train on a straight bridge.
(ii) Straight line
(vi) Straight line
Which of the following are not correct?
(i) The basic unit of time is second.
(ii) Every object moves with a constant speed.
(iii) Distance between two cities is measured in kilometres.
(iv) The time period of a given pendulum is not constant.
(v) The speed of a train is expressed in m/h.
A simple pendulum takes 32 sec. to complete 20 oscillations. What is the time period of the pendulum?
No. of oscillations = 20
Total time taken = 32 sec.
We know that time period of a pendulum is the time taken by it to complete one oscillation. Thus,
Time period =
Therefore, time period of this pendulum will be 1.6 s.
The distance between two stations is 240 km. A train takes 4 hours to cover this distance. Calculate the speed of the train.
Here, it is given that,
The distance between two stations = 240 km
Time taken to cover this distance = 4 hr.
Therefore, speed of the train will be 60 km/h.
The odometer of a car reads 57321.0 km when the clock shows the time 08 : 30 AM. What is the distance moved by the car, if at 08 : 50 AM, the odometer reading has changed to 57336.0 km? Calculate the speed of the car in km/min during this time. Express the speed in km/h also.
In this question, it is given that,
Initial reading of odometer = 57321.0 km
Final reading of odometer = 57336.0 km
Initial time = 08.30 AM
Final time = 08.50 AM
Now, total distance covered = Final reading of odometer – Initial reading of odometer
= 57336.0 km – 57321.0 km
= 15.0 km
Total time taken = Final time – Initial time
= 08.50 AM – 08.30 AM
= 20 min
We know that,
Speed in km/h = 0.75 x 60 (1 hr = 60 min)
= 45 km/hr
Therefore, the distance moved by the car =15 km
and the speed of the car = 0.75 km/min and 45 km/h.
Salma takes 15 minutes from her house to reach her school on a bicycle. If the bicycle has a speed of 2 m/s, calculate the distance between her house and the school.
According to the question,
Speed of the bicycle = 2 m/s
Total time taken = 15 min = 900 sec.
We know that,
The distance covered = Speed x Time
= 2 m/s x 900 sec.
= 1800 m
Therefore, the distance between her house and the school will be 1800 m or 1.8 km.
Show the shape of the distance-time graph for the motion in the following cases:
(i) A car moving with a constant speed.
(ii) A car parked on a side road.
Which of the following releations is correct?
(i) Speed = Distance × Time
(ii) Speed =
(iii) Speed =
(iv) Speed =
(ii) Speed =
The basic unit of speed is:
A car moves with a speed of 40 km/h for 15 minutes and then with a speed of 60 km/h for the next 15 minutes. The total distance covered by the car is:
(i) 100 km
(ii) 25 km
(iii) 15 km
(iv) 10 km
(ii) 25 km
Suppose the two photographs shown in Figures A and B had been taken at an interval of 10 seconds. If a distance of 100 metres is shown by 1 cm in these photographs, calculate the speed of the red car.
Do it yourself.
Figure shows the distance-time graph for the motion of two vehicles A and B. Which one of them is moving faster?
Fig. Distance-time graph for the motion of two cars
A is moving faster.
Which of the following distance-time graphs shows a truck moving with speed which is not constant?
(ii) and (iii).
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