NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Ex 7.2 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Ex 7.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Congruence of Triangles |

Exercise |
Ex 7.2 |

Number of Questions Solved |
10 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles Ex 7.2

**Question 1.**

Which congruence criterion do you use in the following?

Given:

So.

AC = DF

AB = DE

BC = EF

so ∆ ABC = ∆ DEF

Given: ZX = RP

RQ = ZY

∠PRQ = ∠XZY

So, ∆ PQR ≅ ∆ XYZ

Given : ∠MLN = ∠ FGH

∠NML = ∠GFH

ML = GF

So, ∆ LMN ≅ ∆ GFH

Given : EB = DB

AE = BC

∠A = ∠C = 90°

So, ∆ ABE ≅ ∆ CDB

**Solution:**

**(a)** SSS congruence criterion

**(b)** SAS congruence criterion

**(c)** ASA congruence criterion

**(d)** RHS congruence criterion.

**Question 2.**

You want to show that ∆ ART ≅ ∆ PEN,

**(а)** If you have to use SSS criterion, then you need to show

(i)AR = (ii) RT = (iii) AT =

**(b)** If it is given that ∠T = ∠N and you are to use SAS criterion, you need to have

(i) RT = and (ii) PN =

**(c)** If it is given that AT = PN and you are to use ASA criterion, you need to have

(i) ? (ii) ?

**Solution:
**

**Question 3.**

You have to show that ∆ AMP = ∆ AMQ.

In the following proof, supply the missing reasons.

**Solution:
**

**Question 4.**

In ∆ ABC, ∠A = 30°, ∠B = 40° and ∠C = 110°

In ∆ PQR, ∠P = 30°, ∠Q = 40° and ∠R = 110°

A student says that ∆ ABC = ∆ PQR? by AAA congruence criterion. Is he justified’? Why or why not?

**Solution:**

No! he is not justified because AAA is not a criterion for congruence of triangles.

**Question 5.**

In the figure, the two triangles are congruent. The corresponding parts are marked. We can write ∆ RAT = ?

**Solution:**

∆ RAT ≅ ∆ WON

**Question 6.**

Complete the congruence statement:

**Solution:**

∆ BCA = ∆ BTA

∆ QRS = ∆ TPQ

**Question 7.**

In a squared sheet, draw two triangles of equal areas such that

- the triangles are congruent
- the triangles are not congruent. What can you say about their perimeters?

**Solution:
**

**Question 8.**

Draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent.

**Solution:
**

In ∆ ABC and ∆ DEF,

AB = DF (= 2 cm)

BC = ED (= 4 cm)

CA = EF (= 3 cm)

∠BAC = ∠EDF

∠ABC = ∠DEF

But ∆ ABC is not congruent to ∆ DEF.

**Question 9.**

If ∆ ABC and ∆ PQR are to be congruent, name one additional pair of corresponding parts. What criterion did you use?

**Solution:**

BC = RQ by ASA congruence rule.

**Question 10.**

Explain why ∆ ABC ≅ ∆ FED

**Solution:**

∠ABC = ∠FED (= 90°) BC = ED

∠ACB = ∠FDE

∵ The sum of the measures of the three angles of a triangle is 180°.

∆ ABC ≅ ∆ FED (By SAS congruence criterion)

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