NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2.

- Algebraic Expressions and Identities Class 8 Ex 9.1
- Algebraic Expressions and Identities Class 8 Ex 9.3
- Algebraic Expressions and Identities Class 8 Ex 9.4
- Algebraic Expressions and Identities Class 8 Ex 9.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 9 |

Chapter Name |
Algebraic Expressions and Identities |

Exercise |
Ex 9.2 |

Number of Questions Solved |
5 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2

**Question 1.**

**Find the product of the following pairs of monomials:**

**(i)** 4, 7p

**(ii)** – 4p, 7p

**(iii)** – 4p, 7pq

**(iv)** \(4{ p }^{ 3, },\quad -3p\)

**(v)** 4p, 0.

**Solution.**

**Question 2.**

**Find the areas of rectangles with the following pairs of mononials as their lengths and breadths respectively:**

**(i)** (p, q);

**(ii) **(10m, 5n);

**(iii) **(\(20{ x }^{ 2 },\quad 5{ y }^{ 2 }\));

**(iv) **(\(4x,\quad 3{ x }^{ 2 }\));

**(v) **(3mn, 4np).

**Solution.**

**(i) (p, q)**

Length = p

Breadth = q

∴ Area of the rectangle

= Length x Breadth

= pxq

= pq

**(ii) (10m, 5n)**

Length = 10 m

Breadth = 5 n

∴ Area of the rectangle

= Length x Breadth

= (10m) x (5n)

= (10 x 5) x (m x n)

= 50 x (mn)

= 50 mn

**(iii) (\(20{ x }^{ 2 },\quad 5{ y }^{ 2 }\))**

Length = \(20{ x }^{ 2 }\)

Breadth = \(5{ y }^{ 2 }\)

∴ Area of the rectangle

= Length x Breadth

= (\(20{ x }^{ 2 }\)) x (\(5{ y }^{ 2 }\))

= (20 x 5) x (\({ x }^{ 2 }\times { y }^{ 2 }\))

= 100 x (\({ x }^{ 2 }{ y }^{ 2 }\))

= 100\({ x }^{ 2 }{ y }^{ 2 }\)

**(iv) (4x, 3xP)**

Length = 4.x

Breadth = \(3{ x }^{ 2 }\)

∴ Area of the rectangle

= Length x Breadth =

(4x) x (\(3{ x }^{ 2 }\))

= (4 x 3) x (\(x\times { x }^{ 2 }\))

= 12 x \({ x }^{ 3 }\)

= 12×3

**(v) (3mn, 4np)**

Length = 3 mn

Breadth = 4np

∴ Area of the rectangle

= Length x Breadth

= (3mn) x (4np)

= (3 x 4) x (mn) x (np)

= 12 x m x (n x n) x p

= 12\(m{ n }^{ 2 }p\)

**Question 3.**

Complete the table of products.

**Solution.**

**Question 4.**

**Obtain the volume of rectangular boxes with the following length, breadth and height respectively:**

**(i)** \(5a,\quad 3{ a }^{ 2 },\quad 7{ a }^{ 4 }\)

**(ii)** 2p, 4q, 8r

**(iii)** \(xy,\quad 2{ x }^{ 2 }y,\quad 2x{ y }^{ 2 }\)

**(iv)** a, 2b, 3c

**Solution.**

**(i) \(5a,\quad 3{ a }^{ 2 },\quad 7{ a }^{ 4 }\)**

**(ii) 2p, 4q, 8r**

**(iii) \(xy,\quad 2{ x }^{ 2 }y,\quad 2x{ y }^{ 2 }\)**

**(iv) a, 2b, 3c**

**Question 5.**

**Obtain the product of**

**(i)** xy, yz, zx

**(ii)** \(a,\quad -{ a }^{ 2 },\quad { a }^{ 3 }\)

**(iii)** \(2,\quad 4y,\quad 8{ y }^{ 2 },\quad 16{ y }^{ 3 }\)

**(iv)** a, 2b, 3c, 6abc

**(v)** m, – mn, mnp.

**Solution.**

**(i) xy, yz, zx**

Required product

= (xy) x (yz) x (zx)

**(ii) \(a,\quad -{ a }^{ 2 },\quad { a }^{ 3 }\)**

**(iii) \(2,\quad 4y,\quad 8{ y }^{ 2 },\quad 16{ y }^{ 3 }\)**

**(iv) a, 2b, 3c, 6abc**

**(v) m, – mn, mnp.**

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