## Selina Concise Mathematics Class 8 ICSE Solutions Chapter 2 Exponents (Powers)

**Selina Publishers Concise Mathematics Class 8 ICSE Solutions Chapter 2 Exponents (Powers)**

### Exponents Exercise 2A – Selina Concise Mathematics Class 8 ICSE Solutions

Question 1.

Evaluate:

Solution:

Question 2.

If 1125 = 3^{m} x 5^{n}; find m and n.

Solution:

Question 3.

Find x, if 9 × 3^{x} = (27)^{2x-3}

Solution:

### Exponents Exercise 2B – Selina Concise Mathematics Class 8 ICSE Solutions

Question 1.

Compute:

Solution:

Question 2.

Simplify:

(i)

(ii) [(64)^{-2}]^{-3} ÷ [{(-8)^{2}}^{3}]^{2
}(iii) (2^{-3} – 2^{-4}) (2^{-3} + 2^{-4}**)**

Solution:

Question 3.

Evaluate:

Solution:

Question 4.

Simplify:

Solution:

Question 5.

Simplify:

(x^{a+b})^{a-b}.(x^{b+c})^{b-c}.(x^{c+a})^{c-a
} Solution:

Question 6.

Simplify:

(i)

(ii)

Solution:

Question 7.

(i) (a^{-2})^{-2}. (ab)^{-3}

(ii) (x^{n}y^{-m})^{4 }× (x^{3}y^{-2})^{-n
}(iii)

(iv)

(v) (a^{-2}b)^{1/2} × (ab^{-3})^{1/3}

(vi) (xy)^{m-n} . (yz)^{n-1} . (zx)^{1-m}

Solution:

Question 8.

Show that:

Solution:

Question 9.

Evaluate:

Solution:

Question 10.

Evaluate:

Solution:

Question 11.

(m + n)^{-1 }(m^{-1 }+ n^{-1}) = (mn)^{-1}

Solution:

Question 12.

Prove that:

Solution:

Question 13.

Find the values of n, when:

(i) 12^{-5} × 12^{2n+1} = 12^{13} ÷ 12^{7}

(ii) = (a^{3})^{3} ÷ (a^{6})^{-3}

Solution:

Question 14.

Simplify:

Solution:

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