NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.3 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.3.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 8 |

Chapter Name |
Comparing Quantities |

Exercise |
Ex 8.3 |

Number of Questions Solved |
12 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 8 Comparing Quantities Ex 8.3

**Question 1.**

**Calculate the amount and compound interest on**

**Solution.**

**(a) By using year by year calculation**

**(b) By using year by year calculation**

**(c) By using half year by half year calculation**

**(d) By using half-year by half-year calculation**

**Question 2.**

Kamala borrowed ₹ 26,400 from a Bank to buy a scooter at a rate of 15% p.a. compounded yearly. What amount will she pay at the end of 2 years and 4 months to clear the loan?

(Hint: Find A for 2 years if interest is compounded yearly and then find SI on the 2nd year amount for \(\frac { 4 }{ 12 } \) year)

**Solution.**

**Question 3.**

Fabina borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually. Who pays more interest and by how much ?

**Solution.**

**For Fabina**

**Question 4.**

I borrowed ₹ 12,000from Jamshed at 6% per annum simple interest for 2 years. Had I borrowed this sum at 6% per annum compound interest, what excess amount would I have to pay?

**Solution.**

At simple interest

P = ₹ 12000

R = 6% per annum

**Question 5.**

Vasudevan invested ₹ 60,000 on interest at the rate of 12% per annum compounded half yearly. What amount would he get

**(i)** after 6 months?

**(ii)** after 1 year?

**Solution.**

**(i) after 6 months**

P = ₹ 60,000

R = 12% per annum

**(ii) after 1 year**

**Question 6.**

Arif took a loan of ₹ 80,000 from a bank. If the rate of interest is 10% per annum, find the difference in amounts he would be paying after \(1\frac { 1 }{ 2 } \) years if the interest is

**(i)** compounded annually

**(ii)** compounded half yearly

**Solution.**

**(i) compounded annually**

**(ii) compounded half yearly**

**Question 7.**

Maria invested ₹ 8,000 in business. She would be paid interest at the rate of 5% per annum compounded annually. Find

**(i)** the amount credited against her name at the end of the second year.

**(ii)** the interest for the 3rd year.

**Solution.**

**(i)**

**(ii)**

**Question 8.**

Find the amount and the compound interest on ₹ 10,000 for \(1\frac { 1 }{ 2 } \) years at 10% per annum, compounded half yearly. Would this interest be more than the interest he would get if it was compounded annually?

**Solution.**

**Question 9.**

Find the amount which Ram will get on ₹ 4,096 if he gave it for 18 months at \(12\frac { 1 }{ 2 } % \) per annum, interest being compounded half yearly.

**Solution.**

**Question 10.**

The population of a place increased to 54,000 in 2003 at a rate of 5% per annum.

**(i)** find the population in 2001.

**(ii)** what would he its population in 2005?

**Solution.**

**(i)
** Let the population in 2001 be P.

R = 5% p.a.

n = 2 years

**(ii)**

initial population in 2003

**Question 11.**

In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours, if the count was initially 5,06,000.

**Solution.**

Initial count of bacteria

**Question 12.**

A scooter was bought at ₹ 42,000. It’s value depreciated at the rate of 8% per annum. Find its value after one year.

**Solution.**

Initial value of the scooter

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