NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5.

- Practical Geometry Class 7 Ex 10.1
- Practical Geometry Class 7 Ex 10.2
- Practical Geometry Class 7 Ex 10.3
- Practical Geometry Class 7 Ex 10.4

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 10 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 10.5 |

Number of Questions Solved |
3 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.5

**Question 1.**

Construct the right-angled ∆ PQR where m ∠Q = 90°, QR = 8 cm and PR = 10 cm.

**Solution:**

**Steps of Construction**

- Draw QR of length 8 cm.

- At Q, draw QX ⊥ QR.
- With R as centre, draw an arc of radius 10 cm.
- Mark the meeting point of these two as P.

∆ PQR is now obtained.

**Question 2.**

Construct a right-angled triangle whose hypotenuse is 6 cm long and one of the legs is 4 cm long.

**Solution:**

**Steps of Construction**

- Draw QR of length 4 cm.
- At Q, draw QX ⊥ QR.

- With R as centre, draw an arc of radius 6 cm.
- Mark the meeting point of arc and QX as P.

∆ PQR is now obtained.

**Question 3.**

Construct an isosceles right-angled triangle ABC where m ∠ACB = 90° and AC = 6 cm.

**Solution:**

**Steps of Construction**

- Draw AC of length 6 cm.
- At C, draw CX ⊥ CA.

- With C as centre, draw an arc of radius 6 cm to intersect CX at B.
- Join AB.

∆ ACB is now obtained.

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