NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3.

- Practical Geometry Class 7 Ex 10.1
- Practical Geometry Class 7 Ex 10.2
- Practical Geometry Class 7 Ex 10.4
- Practical Geometry Class 7 Ex 10.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 10 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 10.3 |

Number of Questions Solved |
3 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.3

**Question 1.**

Construct ADEF such that DE = 5 cm, DF 3 cm, and m ∠EDF = 90°.

**Solution:**

**Steps of Construction:
**

- Draw a line segment DE = 5cm.
- Draw ∠EDX = 90°.
- With centre D and radius = 3 cm, draw an arc to intersect DX at F.
- Join EF to obtain the required triangle DBF.

**Question 2.**

Construct an isosceles triangle in which the length of each of its equal sides is 6.5 cm and the angle between them is 110°.

**Solution:**

**Steps of Construction**

- Draw a line segment QR of length 6.5 cm.
- At Q, draw QX making 110° with QR, using a protractor.

- With Q as centre, draw an arc of a radius of 6.5 cm. It cuts QX at P.
- Join PR. ∆ PQR is now obtained.

**Question 3.**

Construct ∆ ABC with BC = 7.5 cm, AC = 5 cm and m ∠C = 60°.

**Solution:**

**Steps of Construction:
**

- Draw a line segment BC = 7.5 cm.
- Draw ∠BCX = 60°.
- With C as centre and radius = 5 cm, draw an arc intersecting CX at A.
- Join AB to obtain the required ∆ABC.

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