Students often refer to Maths Mela Class 4 Solutions Chapter 10 Elephants, Tigers, and Leopards Question Answer NCERT Solutions to verify their answers.
Class 4 Maths Chapter 10 Elephants, Tigers, and Leopards Question Answer Solutions
Elephants, Tigers, and Leopards Class 4 Maths Solutions
Class 4 Maths Chapter 10 Solutions
Addition Chart (Pages 150 – 151)
Look at the table given below and discuss how the table is made.
Question 1.
Identify some patterns in the table.
Answer:
(i) Any number plus 0 remains the same.
(ii) Each row and column increase by 1.
(iii) The sum increases by 2 when moving diagonally.
Question 2.
Observe the cells where the number 9 appears in the table. How many times do you see number 9 ? What about other numbers?
Answer:
The number 9 appears 1 0 times in the table.
These are the pairs that add up to 9:
0 + 9
1 + 8
2 + 7
3 + 6
4 + 5
We can find them going from top – right to bottom – left.
What about other numbers?
Some numbers appear only once (like 0 and 24).
Some numbers appear many times (like 12, which appears the – most).
The number of times you see a number depends on how many ways you can add two numbers to get it.
Question 3.
Are there any rows or columns that contain only even numbers or only odd numbers? Explain your observation.
Answer:
No! Every row and column has a mix of even and odd numbers.
When you add an even + odd, you get odd.
When you add odd + odd or even + even, you get even.
Since the numbers being added change (some are odd and some even), the answer changes too!
Question 4.
Look at the window frame highlighted in red colour in the table.
(a) Find the sum of the two numbers in each row.
(b) Find the sum of the two numbers in each column. What do you notice?
(c) Now, find the sum of the numbers in each of the two diagonals marked by arrows. What do you notice?
(d) Now, put the red window frame in other places and find the sums as above. What do you notice?
Answer:
(a) To find the sum of the two numbers in each row of the red frame:
First row (contains 10 and 11): 10 + 11 = 21
Second row (contains 11 and 12): 11 + 12 = 23
(b) To find the sum of the two numbers in each column of the red frame:
First column (contains 10 and 11): 10 + 11 = 21
Second column (contains 11 and 12): 11 + 12 = 23
Just like the sums of the rows, the sums of the columns are also 21 and 23.
(c) Now, let’s find the sum of the numbers in each of the two diagonals marked by arrows:
First diagonal (from top – left to bottom – right, contains 10 and 12): 10 + 12 = 22
Second diagonal (from top – right to bottom – left, contains 11 and 11): 11 + 11 = 22
The sum of the numbers in both diagonals is the same! They both add up to 22.
(d) Now, let’s imagine we put the red window frame in other places in the table and find the sums as we did above.
Let’s try moving the red frame one step to the right. It would now cover the numbers 11,12,12, and 13.
Sum of the first row: 11 + 12 = 23
Sum of the second row: 12 + 13 = 25
Sum of the first column: 11 + 12 = 23
Sum of the second column: 12 + 13 = 25
Sum of the first diagonal: 11 + 13 = 24
Sum of the second diagonal: 12 + 12 = 24
What do you notice?
The sums of the numbers in the rows are different (23 and 25), and they are 2 more than the previous row sums.
The sums of the numbers in the columns are also different (23 and 25), and they are 2 more than the previous column sums.
The sums of the numbers in both diagonals are still the same (both 24), and they are 2 more than the previous diagonal sums.
It seems like when we move the frame, the sums change, but the diagonals within the frame always add up to the same number!
Question 5.
Identify some patterns and relationships among the numbers in the blue window frame.
Answer:
Do it yourself.
Reverse and Add (Page 151)
(a) Take a 2 – digit number say, 27. Reverse its digits (72). Add them (99). Repeat for different 2 – digit numbers.
(b) What sums can we get when we add a 2 – digit number with its reverse?
(c) List down all numbers which when added to their reverse give
(i) 55
(ii) 88
(d) Can we get a 3 – digit sum? What is the smallest 3 – digit sum that . we can get?
Answer:
(a) Take 13. Reverse is 31. By adding 13 + 31 = 44.
Take 52. Reverse is 25. By adding 52 + 25 = 77.
(b) You will get even numbers like: 66,77,88,99,110, etc.
This is because you are always adding two numbers that are mirror images.
(c) (i) 55
Let’s find numbers that when added to their reverse give 55 :
Try 41 → 41 + 14 = 55
Try 23 → 23 + 32 = 55
So, answers are: 41 and 23.
(ii) Try
61 → 61 + 16 = 77 (too small)
62 → 62 + 26 = 88
43 → 43 + 34 = 77
44 → 44 + 44 = 88
So, answers are: 62 and 44.
(d) Let’s try:
65 → reverse is 56 → 65 + 56 = 121
73 + 37 = 110
82 + 28 = 110
Yes, we can get a 3 – digit sum.
Smallest 3 – digit sum is 101 → from 50 + 51
Fill in the blanks with appropriate numbers (Page 151)
Answer:
(a) 2540,2590,2640,2690,2740,2790
(b) 354,1354,2354,3354,4354,5354
(c) 7645,7670,7695,7720,7745,7770,7795
How Many Animals?
Maharashtra has 444 tigers. Madhya Pradesh has 341 more tigers than Maharashtra. Uttarakhand has 116 tigers more than Maharashtra.
(Page 154)
(a) How many tigers does
Answer:
(b) How many tigers does Madhya Pradesh have?
Answer:
(c) How many tigers does
Answer:
(d) How many tigers are there Madhya Pradesh and in total across the three Uttarakhand have? states?
Answer:
More or Less (Page 155)
The population of leopards as per the 2022 census was 8820 in the Central India and the Eastern Ghats. It had increased by 749 in comparison to the number of leopards in 2018 in the same region. How many leopards were there in 2018 ?
_____ leopards were there in 2018.
Write the number of animals on this map based on the data from the problems in the previous pages.
Answer:
In 2022, there were 8820 leopards and this number is 749 more than in 2018. To find 2018 population, we need to subtract:
8820 – 749 = 8071.
There were 8071 leopards in 2018.
Do it yourself.
Let Us Do (Pages 157 – 160)
Question 1.
The board in the ticket office in the Kaziranga National Park shows the following:
(a) How many more visitors came in December than in November?
Answer:
December visitors = 8591
November visitors = 6415
We subtract to.find the difference:
8591 – 6415 = 2176
2176 more visitors came in December than in November.
(b) The number of visitors in November is 1587 more than October. How many visitors were there in October?
Answer:
November visitors = 6415
Difference = 1587
We subtract to find October visitors:
6415 – 1587 = 4828
4828 visitors came in October.
Question 2.
In a juice making factory, women make different types of juices as given below:
(a) The number of bottles of guava juice is 759 more than the number of bottles of pineapple juice. Find the number of bottles of guava juice.
Answer:
Pineapple juice = 1348 bottles
Guava juice is 759 more than pineapple juice
Calculation: 1348 + 759 = 2107 bottles
Guava juice = 2107 bottles
(b) The number of bottles of orange juice is 1257 more than the number of bottles of guava juice and 1417 less than the number of bottles of passion fruit juice. How many bottles of orange juice are made in a month?
Answer:
Orange juice is 1257 more than guava juice
Guava juice = 2107 bottles
Calculation: 2107 + 1257 = 3364 bottles
Orange juice = 3364 bottles
(c) Is the total number of bottles of guava juice and orange juice more or less than the number of bottles of passion fruit juice? How much more or less?
Answer:
Guava + Orange = 2107 + 3364 = 5471
Passion Fruit = 4781
Difference: 5471 – 4781 = 690 more
Total of guava and orange juice is 690 more than passion fruit juice.
Question 3.
In a small town, the following vehicles were registered in the year 2022. Find the number of vehicles as per the conditions given below.
(a) The number of buses is 253 more than the number of jeeps. How many buses are there in the town?
Answer:
Buses = Jeeps + 253
Buses = 6304 + 253 = 6557
(b) The number of tractors is 5247 less than the number of buses. How many tractors are in the town?
Answer:
Tractors = Buses – 5247
Tractors = 6557 – 5247 = 1310
(c) The number of taxis is 1579 more than the number of tractors? How many taxis are there?
Answer:
Taxis = Tractors + 1579
Taxis = 1310 + 1579 = 2889
(d) Arrange the numbers of each type of vehicle from lowest to highest.
Answer:
Tractors = 1310
Taxis = 2889
Jeeps = 6304
Buses = 6557
Tractors < Taxis < Jeeps < Buses
Question 4.
Solve
(a) 1459 + 476
(b) 3863 + 4188
(c) 5017 + 899
(d) 4285 + 2132
(e) 3158 + 1052
(f) 7293 – 2819
(g) 3105 – 1223
(h) 8006 – 5567
(i) 5000 – 4124
(j) 9018 – 487
Answer:
(a) 1459 + 476 = 1935
(b) 3863 + 4188 = 8051
(c) 5017 + 899 = 5916
(d) 4285 + 2132 = 6417
(e) 3158 + 1052 = 4210
(f) 7293 – 2819 = 4474
(g) 3105 – 1223 = 1882
(h) 8006 – 5567 = 2439
(i) 5000 – 4124 = 876
(j) 9018 – 487 = 8531
Question 5.
The children in a school in Chittoor are planning to organise a Baal Mela in their school.
Raju, Rani and Roja decided to raise some money to make arrangements for the mela. The money is available in notes of 500,100,50,10 and coins of 5,2 and 1 . They decide to put the money in the School Panchayat Bank.
Help each of the children fill the deposit slip given below.
Different combinations of notes can give the same amount. Can you guess a possible combination of notes they might have? Fill in the amounts appropriately.
Answer:
Final Deposit Slip for Raju:
| Type of Note/Coin | No. of Notes/Coins | Amount |
| 500 | 3 | 1500 |
| 100 | 3 | 300 |
| 50 | 2 | 100 |
| 10 | 14 | 140 |
| 5 | 1 | 5 |
| 2 | 0 | 0 |
| 1 | 0 | 0 |
| Total | 2045 |
Amount in numbers for Raju: ₹2045
Amount in words for Raju: Two thousand forty – five rupees
Answer:
Deposit Slip for Rani:
| Type of Note/Coin | No. of Notes/Coins | Amount |
| 500 | 6 | 3000 |
| 100 | 4 | 400 |
| 50 | 1 | 50 |
| 10 | 10 | 100 |
| 5 | 5 | 25 |
| 2 | 1 | 2 |
| 1 | 1 | 1 |
| Total | 3578 |
Amount in numbers for Rani: ₹ 3578
Amount in words for Rani: Three thousand five hundred seventyeight rupees
Answer:
Deposit Slip for Roja:
| Type of Note/Coin | No. of Notes/Coins | Amount |
| 500 | 2 | 1000 |
| 100 | 2 | 200 |
| 20 | 1 | 20 |
| 10 | 2 | 20 |
| Total | 1240 |
Amount in numbers for Roja: ₹1240
Amount in words for Roja: One thousand two hundred forty rupees
Let Us Solve (Page 161)
Question 1.
Solve
Answer:
Question 2.
Arrange the following in columns and solve in your notebook.
Answer:
(a) 3683 – 971 = 2712
(b) 8432 – 46 = 8386
(c) 4011 – 3666 = 0345
(d) 5203 – 2745 = 2458
(e) 1465 + 632 = 2097
(f) 3567 + 77 = 3644
(g) 8263 + 3737 = 12000
(h) 5429 + 3287 = 8716
Let Us Solve (Pages 162 – 163)
Question 1.
Find easy ways to solve the following problems. Write the answers in the given space. Share your thinking with the grade.
Answer:
(a) 8787 – 99
Easy way: Subtract 100, then add 1
8787 – 100 = 8687
8687 + 1 = 8688
(b) 4596 + 104
Easy way: Add 100, then add 4
4596 + 100 = 4696
4696 + 4 = 4700
(c) 3459 + 21
Easy way: Add 20, then add 1
3459 + 20 = 3479
3479 + 1 = 3480
(d) 5010 + 95
Easy way: Add 100, then subtract 5
5010 + 100 = 5110
5110 – 5 = 5105
(e) 4990 + 310
4990 + 10 = 5000
5000 + 300 = 5300
(f) 7844 – 15
7844 – 10 = 7834
7834 – 5 = 7829
(g) 260 + 240
260 + 240 = 500
(h) 1575 – 125
Subtract 100 = 1475
Subtract 25 = 1450
(i) 3999 + 290
Add 1 to make 4000: 3999 + 1 = 4000
Then add 289: 4000 + 289 = 4289
Question 2.
Use the signs <, =, > as appropriate to compare the following without actually calculating. Try to reason them out and share in grade.
Answer:
1. 54 + 97 > 54 + 90
Same first number, but 97 is greater than 90 .
2. 84 – 68 < 90 – 68
Same number being subtracted, but 90 is more than 84 .
3. 76 + 85 < 80 + 86 Both numbers on the right side are greater than those on the left. 4. 73 – 54 > 73 – 56
Same number being subtracted from, but 54 is less than 56, so more is left on the left side.
Question 3.
Use the given information to find the values. Share your reasoning with the grade.
Answer:
1. Given: 139 + 175 = 314
So, 314 – 175 = 139 (reversing the addition)
2. Given: 845 – 394 = 451
Then: 845 – 395 means subtracting 1 more
So, the result will be 1 less:
451 – 1 = 450
3. Given: 354 + 167 = 521
Now: 354 + 168 means adding 1 more
So, the result will be 1 more:
521 + 1 = 522
4. Given: 456 + 209 = 665
Now: 446 + 219 – one number is 10 less, the other is 10 more So, total remains the same:
Answer is still 665.
(Page 163)
Question 1.
Add
(a) 2783 + 378
(b) 8948 + 97
(c) 7006 + 367
(d) 8009 + 485
(e) 6062 + 3809
(f) 3792 + 2688
(g) 4999 + 3888
(h) 5005 + 4895
(i) 5768 + 4053
(j) 3480 + 479
Answer:
(a) 2783 + 378 = 3161
(b) 8948 + 97 = 9045
(c) 7006 + 367 = 7373
(d) 8009 + 485 = 8494
(e) 6062 + 3809 = 9871
(f) 3792 + 2688 = 6480
(g) 4999 + 3888 = 8887
(h) 5005 + 4895 = 9900
(i) 5768 + 4053 = 9821
(j) 3480 + 479 = 3959
Question 2.
Subtract
(a) 4456 – 2768
(b) 5300 – 467
(c) 8067 – 4546
(d) 5302 – 1034
(e) 8004 – 3107
(f) 3400 – 897
(g) 9382 – 4857
(h) 7561 – 2933
(i) 6478 – 5986
(j) 3444 – 2555
Answer:
(a) 4456 – 2768 = 1688
(b) 5300 – 467 = 4833
(c) 8067 – 4546 = 3521
(d) 5302 – 1034 = 4268
(e) 8004 – 3107 = 4897
(f) 3400 – 897 = 2503
(g) 9382 – 4857 = 4525
(h) 7561 – 2933 = 4628
(i) 6478 – 5986 = 492
(j) 3444 – 2555 = 889
Question 3.
Fill the squares with the numbers 1 – 9. The difference between any two neighbouring squares (connected by a line) must be odd.
Can you find other ways to fill the squares?
Can you do the same thing such that the difference between any two neighbouring squares is even?
Answer:
Part 1: Fill the Squares with Numbers 1 – 9 (Odd Differences)
Rule: When two squares are connected by a line, one number must be odd (1,3,5,7,9) and the other must be even (2,4,6,8).
Example Solution:
Check:
1(odd) ↔ 6(even) → difference = 5(odd)
6(even) ↔ 3(odd) → difference = 3(odd)
1(odd) ↔ 8(even) → difference = 7(odd)
and so on for all connected squares.
Part 2: Fill the Squares with Numbers 1 – 9 (Even Differences)
Rule: When two squares are connected by a line, both numbers must be odd (1, 3, 5, 7, 9) or both must be even (2, 4, 6, 8).
Problem:
We have 5 odd and 4 even numbers.
In a connected grid (like a 3 × 3 square), we cannot separate them fully into odd and even groups without breaking the rule.
Conclusion:
This puzzle cannot be solved with numbers 1 – 9 if all connected squares must have an even difference.
Summary:
1. Odd differences: Possible! Example solutions above.
2. Even differences: Impossible with numbers 1 – 9 in a connected grid.