Students often refer to Maths Mela Class 4 Solutions Chapter 13 The Transport Museum Question Answer NCERT Solutions to verify their answers.
Class 4 Maths Chapter 13 The Transport Museum Question Answer Solutions
The Transport Museum Class 4 Maths Solutions
Class 4 Maths Chapter 13 Solutions
Mystery Matrix (Page 184)
Fill the yellow boxes with 1-digit numbers (multiplicands and multipliers) such that you get the products given in the white boxes. Fill the remaining white boxes with appropriate products.
Answer:
The product of the numbers in each row is given in the orange boxes. The product of the numbers in each column is given in the blue boxes. Identify appropriate numbers to fill the blank boxes.
Answer:
Times-10 (Pages 184-185)
Match each problem with the appropriate pictorial representation and write the answer.
Answer:
What is 10 × 10 = 10Tens = 100
Constructing Tables (Page 185)
How many pebbles are there in this arrangement?
Answer:
There are 75 pebbles in this arrangement.
5 × 15 = 5 × 10 and 5 × 5
= 50 + 25 = 75 pebbles
Recall the times-table that we created in Grade 3. Now construct a times-15 table. You may use the arrangement given below and split the columns into 10 and 5 for ease of counting, as shown on the previous page.
How can we find 1 × 15, 2 × 15, …… with this?
Question 1.
What patterns do you see in this table?
Question 2.
Compare the times- 15 table with the times-5 table. What similarities and differences do you notice?
What times-table is this? ______
How did we get this?
Answer:
Observed pattern
- All numbers in the times-15 table are multiples of 5.
- The times-15 table is 3 times the times-5 table (e.g., 2 × 5 = 10 → 2 × 15 = 30).
- Each step in the times-15 table increases by 15, just like how the times- 5 table increases by 5.
How did we get this?
In the orange table at the bottom:
Multiply the times-5 result by 3 to get the times-15 result.
E.g.:
2 × 5 = 10
10 × 3 = 30 → 2 × 15 = 30
Question 3.
Construct other times-tables for numbers from 11 to 20 , as you did for 15.
Answer:
Do yourself.
Question 4.
As you compared the times-5 table with the times-15 table, compare the times- 1 table with the times-11 table, the times-2 table with the times-12 table, and so on. Share your observations.
Answer:
Do yourself.
Making tables by splitting into equal groups (Pages 187-188)
What other times-tables can be constructed by splitting into equal groups and doubling? Give examples.
Multiples of 10 (Pages 188-190)
Find the answers to the following:
Answer:
(a) 15 × 10 = 15 Tens = 150
(b) 16 × 10 = 16 Tens = 160
(c) 19 × 10 = 19 Tens = 190
(d) 20 × 10 = 20 Tens = 200
Bonus box:
10 × 10 = 100
2 times (i.e., double of) 10 × 10 = 200
Now think and answer the following problems.
Answer:
30 × 10 = 300
50 × 10 = 500
40 × 10 = 400
60 × 10 = 600
70 × 10 = 700
80 × 10 = 800
Let us find the number of people who can travel in 26 tempo travellers.
26 × 10 = 260 travellers.
Answer the following questions. Share your thoughts.
Answer:
(a) 21 × 10 = 210
(b) 42 × 10 = 420
(c) 65 × 10 = 650
(d) 38 × 10 = 380
(e) 53 × 10 = 530
(f) 87 × 10 = 870
Solve the following problems. Share your thoughts.
Answer:
A Day at the Transport Museum (Pages 190-191)
Answer:
Total no. of coaches = 10 + 10 + 1 + 2 = 23
Let Us Solve (Page 192)
Also, identify remainder (if any) in the division problems.
(a) 25 × 34
(e) 125 ÷ 15
(b) 16 × 43
(f) 94 ÷ 11
(c) 68 × 12
(g) 440 ÷ 22
(d) 39 × 13
(h) 508 ÷ 18
Answer:
(a) 25 × 34 = 850
(b) 16 × 43 = 688
(c) 68 × 12 = 816
(d) 39 × 13 = 507
(e) 125 ÷ 15 = 8, R = 5
(f) 94 ÷ 11 = 8, R = 6
(g) 440 ÷ 22 = 20, R = 0
(h) 508 ÷ 18 = 28, R = 4
Multiples of 100 (Pages 192-197)
Answer:
2 × 100 = 2 Hundreds = 200
3 × 100 = 3 Hundreds = 3 0 0
5 × 100 = 5 Hundreds = 500
8 × 100 = 8 Hundreds = 800
Answer:
12 × 100 = 1200
15 × 100 = 1500
20 × 100 = 20 Hundreds = 2000
27 × 100 = 2700
70 × 100 = 7000
Now answer the following questions. Share your thoughts.
Answer:
Answer:
11 × 100 = 1100
11 × 200 = 2200
22 × 100 = 2200
22 × 200 = 4400
Answer the following questions. Share your thoughts.
Answer:
18 × 100 = 1800
5 × 500 = 2500
14 × 300 = 4200
7 × 800 = 5600
15 × 200 = 3000
23 × 200 = 4600
Find the answers in Set A. Examine the relationships between the problems and the answers in Set A carefully. Then use this understanding to find the answers in Set B.
Answer:
(c) (1)
44 × 10 = 440
22 × 20 = 440
(2)
16 × 100 = 1 6 0 0
4 × 400 = 1 6 0 0
Let Us Solve (Page 197)
Also, identify remainder (if any) in the division problems.
(a) 237 × 28
(b) 140 × 16
(c) 389 × 57
(d) 807 ÷ 24
(e) 692 ÷ 33
(f) 996 ÷ 45
Answer:
(a) 237 × 28 = 6,636
(b) 140 × 16 = 2,240
(c) 389 × 57 = 22,173
(d) 807 ÷ 24 = 33, Remainder = 15
(e) 692 ÷ 33 = 20, Remainder = 32
(f) 996 ÷ 45 = 22, Remainder = 6
Dividing by 10 and 100 (Pages 197-198)
A farmer packs his rice in sacks of 10 kg each.
(a) If he has 60 kg of rice, how many sacks does he need?
Answer:
60 ÷ 10 = 6 sacks
(b) If he has 600 kg of rice, how many sacks does he need?
Answer:
600 ÷ 10 = 60 sacks.
If a sack of rice weighs 100 kg then how many sacks does he need for 600 kg of rice? 6
60 ÷ 10 = 6
600 ÷ 10 = 6 0
600 ÷ 100 = 6
Find the answers to the following questions. Share your thoughts in grade.
Answer:
40 ÷ 10 = 4 & 4 ÷ 2 = 2 & 400 ÷ 2 = 2 0 0
400 ÷ 10 = 4 0 & 40 ÷ 20 = 2 & 400 ÷ 20 = 2 0
400 ÷ 100 = 4 & 400 ÷ 200 = 2 & 400 ÷ 200 = 2
Think and answer. Write the division statement in each case.
1. Manku the monkey sees 870 bananas in the market. Each bunch has 10 bananas. How many bunches are there in the market? __________
Answer:
Division Statement: 870 ÷ 10 = 87
There are 87 bunches in the market.
2. Rukhma Bi wants to distribute ₹ 1000 /- equally among her 10 grandchildren on the occasion of Eid.
How much money will each of them get? ______
Answer:
Division Statement: 1000 ÷ 10 = 100
Each of them will get ₹100.
Let Us Solve (Pages 198-200)
1. The oldest long-distance train of the Indian Railways is the Punjab Mail which ran between Mumbai and Peshawar. Its first journey was on 12 October 1912. Do you know how many coaches it had on its first journey? It had 6 coaches: 3 carrying 96 passengers and 3 for goods.
(a) How many people travelled in each coach on the first journey?
Answer:
We know that 3 coaches carried a total of 96 passengers. To find the number of people in each passenger coach, we need to divide the total number of passengers by the number of passenger coaches.
Division Statement: 96 ÷ 3 = 32
32 people travelled in each passenger coach on the first journey.
(b) This train has been running for 106 years now. It runs between Mumbai, Maharashtra and Ferozepur, Punjab. It has 24 coaches. Each coach can carry 72 passengers. How many people can travel on this train?
Answer:
We know the number of passenger coaches (24) and the capacity of each coach (72). To find the total number of people the train can carry, we need to multiply the number of coaches by the capacity of each coach.
24 × 72 = people can travel on this train.
Question 2.
Amala and her 35 classmates, along with 6 teachers, are going on a school trip to Goa. They are using the doubledecker “hop on hop off” sightseeing bus to explore the city.
(a) 2 people can sit on every seat of the bus. There are 15 seats in the lower deck and 10 in the upper deck. How many seats will they need to occupy? Are there enough seats for everyone?
Answer:
Lower deck seats + Upper deck seats = 15 + 10 = 25 seats
Since 2 people can sit on each seat, the total capacity is:
Total seats × 2 people/seat = 25 × 2 = 50 people
There are 42 people in the group. (35 + 1 + 6 = 42)
They will need to occupy 42 seats. Yes, there are enough seats for everyone.
(b) Find the total cost of the tickets for all children.
Answer:
Amala + her 35 classmates = 1 + 35 = 36 children
Total cost for children = Number of children × Ticket price per child = 36 × 359 = 12924
The total cost of the tickets for all children is ₹ 12924.
(c) What is the cost of the tickets for all teachers?
Answer:
Total cost for teachers = Number of teachers × Ticket price per teacher
= 6 × 899 = 5394
The total cost of the tickets for all teacher is ₹5394.
Question 3.
Kedar works in a brick kiln.
(a) The kiln makes 125 bricks in a day. How many bricks can be made in a month?
Answer:
Total bricks in a month
= Number of bricks per day × Number of days in a month
= 125 × 30 = 3,750
The kiln can make 3,750 bricks in a month.
(b) Each brick is sold in the market for ₹ 9. How much money can they earn in a month?
Answer:
Money earned in a month = Total bricks in a month × Selling price per brick
= 3750 × 9 = 33750
They can earn ₹ 33,750 in a month.
Question 4.
Chilika lake in Odisha is the largest saltwater lake in India. It is famous for the Irrawaddy dolphins. Boats can be hired to go see the dolphins. The trip from Puri includes a bus ride followed by a boat ride. Eight people will be going on the trip.
A bus ticket from Puri to Satapada costs ₹ 60.
A two-hour boat ride for 8 people costs ₹ 1200.
How much money do we need to spend on each person?
Answer:
Total cost of the bus tickets for 8 people:
Number of people × Cost per bus ticket = 8 × ₹ 60 = ₹ 480
Total cost of the trip (bus + boat)
= Total cost of bus tickets + Cost of boat ride
= ₹ 480 + ₹ 1200 = ₹ 1680
Cost per person: Total cost of the trip / Number of people
= ₹ 1680 / 8 = ₹ 210
We need to spend ₹ 210 on each person.
Question 5.
Find the multiplication and division sentences below. Shade the sentences. How many can you find? Some are done for you.
Answer:
Question 6.
Solve
(a) 35 × 76
(b) 267 × 38
(c) 498 × 9
(d) 89 × 42
(e) 55 × 23
(f) 345 × 17
(g) 66 × 22
(h) 704 × 11
(i) 319 × 26
(j) 459 ÷ 3
(k) 774 ÷ 18
(1) 864 ÷ 26
(m) 304 ÷ 12
(n) 670 ÷ 9
(o) 584 ÷ 25
(p) 900 ÷ 15
(q) 658 ÷ 32
(r) 974 ÷ 9
Answer:
(a) 35 × 76 = 2660
(b) 267 × 38 = 10146
(c) 498 × 9 = 4482
(d) 89 × 42 = 3738
(e) 55 × 23 = 1265
(f) 345 × 17 = 5865
(g) 66 × 22 = 1452
(h) 704 × 11 = 7744
(i) 319 × 26 = 8294
(j) 459 ÷ 3 = 153, Remainder = 6
(k) 774 ÷ 18 = 43, Remainder = 6
(l) 864 ÷ 26 = 33, Remainder = 6
(m) 304 ÷ 12 = 25, Remainder = 4
(n) 670 ÷ 9 = 74, Remainder = 4
(o) 584 ÷ 25 = 23, Remainder = 9
(p) 900 ÷ 15 = 60, Remainder = 0
(q) 658 ÷ 32 = 20, Remainder = 18
(r) 974 ÷ 9 = 108, Remainder = 2
Chinnu’s Coins (Pages 201-202)
Question 1.
Five friends plan to visit an amusement park nearby. Each of them uses different notes and coins to buy the ticket. The cost of the ticket is ₹ 750.
- Bujji has brought all notes of ₹ 200.
- And Munna has brought all notes of ₹ 50.
- Whereas Balu has brought all notes of ₹ 20.
- And guess what, Chinnu has all coins of ₹ 5.
- And Sansu has all coins of ₹ 2.
(a) Find out how many notes/coins each child has to bring to buy the ticket.
(b) Which of these children will not receive any change from the cashier?
(c) How long would the cashier take to count Chinnu’s coins?
Answer:
(a) Ticket cost = ₹ 750
Bujji (₹ 200 notes):
750 ÷ 200 = 3 notes (₹ 600) → Needs 1 more note
4 notes = ₹ 800 → will get ₹ 50 back
So, 4 notes of ₹ 200
Munna (₹50 notes):
750 ÷ 50 = 15 notes of ₹ 50
Balu (₹20 notes):
750 ÷ 20 = 37.5 → Not a whole number
Needs 38 notes = ₹ 760 → will get ₹ 10 back
Chinnu (₹5 coins):
750 ÷ 5 = 150 coins
Sansu (₹2 coins):
750 ÷ 2 = 375 \text { coins
(b) Munna → 15 × ₹ 50 = ₹ 750 → Exact amount
Chinnu → 150 × ₹ 5 = ₹ 750 → Exact amount
Sansu → 375 × ₹ 2 = ₹ 750 → Exact amount
Munna, Chinnu and Sansu will not receive any change.
(c) Assuming it takes 2 seconds per coin:
– 150 coins × 2 seconds = 300 seconds
→ 300 ÷ 60 = 5 minutes
It would take about 5 minutes to count Chinnu’s coins.
Question 2.
Observe the following multiplications. The answers have been provided.
In each case, do you see any pattern in the two numbers and their product? (Hint: Look at the coloured digits!)
For what other multiplication problems will this pattern hold?
Find 5 such examples.
Answer:
5 Patterned Multiplication Examples:
1. 12 × 12 = 144
2. 15 × 11 = 165
3. 16 × 11 = 176
4. 12 × 14 = 168
5. 18 × 11 = 198
Question 3.
Assume each vehicle is travelling with full capacity. How many people can travel in each of these vehicles? Match them up.
Answer:
