NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2.

- Perimeter and Area Class 7 Ex 11.1
- Perimeter and Area Class 7 Ex 11.3
- Perimeter and Area Class 7 Ex 11.4
- Perimeter and Area Class 7 MCQ

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 11 |

Chapter Name |
Perimeter and Area |

Exercise |
Ex 11.2 |

Number of Questions Solved |
8 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2

**Question 1.**

Find the area of the following parallelograms :

**Solution:
**

**Question 2.**

Find the area of each of the following triangles :

**Solution:
**

**Question 3.**

Find the missing values :

**Solution:
**

**Question 4.**

Find the missing values :

**Solution:
**

**Question 5.**

PQRS is a parallelogram (in Figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM =7.6 cm. Find :

**(a)** the area of the parallelogram PQRS

**(b)** QN, if PS = 8 cm.

**Solution:**

**(a)** Area of the parallelogram PQRS = base × height = SR × QM = 12 × 7.6 cm^{2} = 91.2 cm^{2}

**(b)** Area of the parallelogram PQRS = base × height = PS × QN

⇒ 91.2 = 8 × QN

⇒ QN = cm

⇒ QN = 11.4 cm.

**Question 6.**

DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (in Figure). If the area of parallelogram is 1470 cm2, AB = 35 cm and AD = 49 cm, find the length of BM and DL.

**Solution:
**

**Question 7.**

∆ ABC is right-angled at A (in Figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ ABC. Also find the length of AD.

**Solution:
**

**Question 8.**

∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?

**Solution:
**

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