## RS Aggarwal Class 6 Solutions Chapter 10 Ratio, Proportion and Unitary Method Ex 10D

These Solutions are part of RS Aggarwal Solutions Class 6. Here we have given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10D.

**Other Exercises**

- RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10A
- RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10B
- RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10C
- RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10D

**OBJECTIVE QUESTIONS**

**Mark against the correct answer in each of the following :**

**Question 1**

**Solution:**

(d) \(\\ \frac { 92 }{ 115 } \)

**Question 2.**

**Solution:**

(a) \(\\ \frac { 57 }{ x } \)

= \(\\ \frac { 51 }{ 85 } \)

**Question 3.**

**Solution:**

(a) \(\\ \frac { 25 }{ 35 } \)

= \(\\ \frac { 45 }{ x } \)

**Question 4.**

**Solution:**

(c) \(\\ \frac { 4 }{ 5 } \)

= \(\\ \frac { x }{ 35 } \)

**Question 5.**

**Solution:**

(b) \(\\ \frac { a }{ b } \)

= \(\\ \frac { c }{ d } \)

=>ad = bc

**Question 6.**

**Solution:**

(b) a : b :: b : c

**Question 7.**

**Solution:**

(b) \(\\ \frac { 5 }{ 8 } \) < \(\\ \frac { 3 }{ 4 } \) => 4 x 5 < 3 x 8 => 20 < 24

**Question 8.**

**Solution:**

Total amount = Rs 760

Ratio A : B = 8 : 11

**Question 9.**

**Solution:**

(d) largest = \(\\ \frac { 252\times 7 }{ 5+7 } \)

= \(\\ \frac { 252\times 7 }{ 12 } \)

= 21 x 7

= 147

**Question 10.**

**Solution:**

(b) largest = \(\\ \frac { 90\times 5 }{ 1+3+5 } \)

= \(\\ \frac { 90\times 5 }{ 9 } \)

= 50 cm

**Question 11.**

**Solution:**

(c) total strength of school

largest = \(\\ \frac { 840 }{ 5 } \) x (12 + 5)

= \(\\ \frac { 840\times 17 }{ 5 } \)

= 168 x 17

= 2856

**Question 12.**

**Solution:**

(b) Cost of 12 pens = Rs 138

Cost of 1 pen = Rs \(\\ \frac { 138\times 14 }{ 12 } \)

and cost of 14 pens = Rs 161

**Question 13.**

**Solution:**

(b) \(\\ \frac { 24\times 15 }{ 8 } \)

= 45 days

**Question 14.**

**Solution:**

(a) \(\\ \frac { 26\times 40 }{ 20 } \)

= 52 men

**Question 15.**

**Solution:**

(b) In 6 L of petrol, a car covers = 111 km

In 1 L, it will cover = \(\\ \frac { 111 }{ 6 } \) km

and in 10 L it will cover = \(\\ \frac { 111\times 10 }{ 6 } \) km

= 185 km

**Question 16.**

**Solution:**

(a) \(\\ \frac { 28\times 550 }{ 700 } \)

= 22 days

**Question 17.**

**Solution:**

Ratio in the angles of triangle

= 3 : 1 : 2

**Question 18.**

**Solution:**

(b) Ratio in length and breadth of a rectangle = 5 : 4

Width = 36 m

Length = \(\\ \frac { 5 }{ 4 } \) x 36 m

= 45m

**Question 19.**

**Solution:**

Bus covers in 3 hrs = 195 km

It will cover in 1 hr = \(\\ \frac { 195 }{ 3 } \) = 65 km

**Question 20.**

**Solution:**

1 dozen = 12 bars

Cost of 5 bars of soap = Rs.82.50

**Question 21.**

**Solution:**

Total pencils in 30 packets of 8 pencils

= 30 x 8= 240

and total pencils of 25 packets of 12

pencils = 25 x 12 = 300

Now cost of 240 pencils = Rs. 600

Then cost of 1 percent = Rs. \(\\ \frac { 600 }{ 24 } \)

and cost of 300 pencils = Rs. \(\\ \frac { 600\times 300 }{ 240 } \)

= Rs 750 (b)

**Question 22.**

**Solution:**

Journey of 75 km costs = Rs 215

Cost of 1 km = Rs \(\\ \frac { 215 }{ 75 } \)

**Question 23.**

**Solution:**

1st term = 12

2nd term = 21

fourth term = 14

**Question 24.**

**Solution:**

10 boys dig a patch in = 12 hrs

1 boy will dig it in = 12 x 10 hours

Hope given RS Aggarwal Solutions Class 6 Chapter 10 Ratio, Proportion and Unitary Method Ex 10D are helpful to complete your math homework.

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