Check the below NCERT MCQ Questions for Class 10 Maths Chapter 7 Coordinate Geometry with Answers Pdf free download. MCQ Questions for Class 10 Maths with Answers were prepared based on the latest exam pattern. We have provided Coordinate Geometry Class 10 Maths MCQs Questions with Answers to help students understand the concept very well.
Students can also refer to NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry for better exam preparation and score more marks.
Coordinate Geometry Class 10 MCQs Questions with Answers
Question 1.
The distance of the point P(2, 3) from the x-axis is
(a) 2
(b) 3
(c) 1
(d) 5
Answer
Answer: (b) 3
Question 2.
The distance between the points A(0, 6) and B(0, -2) is
(a) 6
(b) 8
(c) 4
(d) 2
Answer
Answer: (b) 8
Question 3.
The distance of the point P(-6, 8) from the origin is
(a) 8
(b) 2√7
(c) 10
(d) 6
Answer
Answer: (c) 10
Question 4.
The distance between the points (0, 5) and (-5, 0) is
(a) 5
(b) 5√2
(c) 2√5
(d) 10
Answer
Answer: (b) 5√2
Question 5.
AOBC is a rectangle whose three vertices are A(0, 3), O(0, 0) and B(5, 0). The length of its diagonal is
(a) 5
(b) 3
(c) \(\sqrt{34}\)
(d) 4
Answer
Answer: (c) \(\sqrt{34}\)
Question 6.
The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is
(a) 5
(b) 12
(c) 11
(d) 7 + √5
Answer
Answer: (b) 12
Question 7.
The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is
(a) 14
(b) 28
(c) 8
(d) 6
Answer
Answer: (c) 8
Question 8.
The points (-4, 0), (4, 0), (0, 3) are the vertices of a
(а) Right triangle
(b) Isosceles triangle
(c) Equilateral triangle
(d) Scalene triangle
Answer
Answer: (b) Isosceles triangle
Question 9.
The point which divides the lines segment joining the points (7, -6) and (3, 4) in ratio 1 : 2 internally lies in the
(a) I quadrant
(b) II quadrant
(c) III quadrant
(d) IV quadrant
Answer
Answer: (d) IV quadrant
Question 10.
The point which lies on the perpendicular bisector of the line segment joining the points A(-2, -5) and B(2, 5) is
(a) (0, 0)
(b) (0, 2)
(c) (2, 0)
(d) (-2, 0)
Answer
Answer: (a) (0, 0)
Question 11.
The fourth vertex D of a parallelogram ABCD whose three vertices are A(-2, 3), B(6, 7) and C(8, 3) is
(a) (0, 1)
(b) (0, -1)
(c) (-1, 0)
(d)(1, 0)
Answer
Answer: (b) (0, -1)
Question 12.
If the point P(2, 1) lies on the line segment joining points A(4, 2) and B(8, 4), then
(a) AP = \(\frac{1}{3}\) AB
(b) AP = PB
(c) PB = \(\frac{1}{3}\) AB
(d) AP = \(\frac{1}{2}\) AB
Answer
Answer: (d) AP = \(\frac{1}{2}\) AB
Question 13.
If P (\(\frac{α}{3}\), 4) is the mid-point of the line segment joining the points Q(-6, 5) and R(-2, 3), then the value of‘a’ is
(a) -4
(b) -12
(c) 12
(d) -6
Answer
Answer: (b) -12
Question 14.
The perpendicular bisector of the line segment joining the points A(l, 5) and B(4, 6) cuts the y-axis at
(a) (0, 13)
(b) (0, -13)
(c) (0, 12)
(d) (13, 0)
Answer
Answer: (a) (0, 13)
Question 15.
The coordinates of the point which is equidistant from the three vertices of the ΔAOB as shown in the figure.
(a) (x, y)
(b) (y, x)
(c) (\(\frac{x}{2}\), \(\frac{y}{2}\))
(d) (\(\frac{y}{2}\), \(\frac{x}{2}\))
Answer
Answer: (a) (x, y)
Question 16.
A circle drawn with origin as the centre passes through (\(\frac{13}{2}\), 0). The point which does not lie in the interior of the circle is
(a) (-\(\frac{3}{4}\), 1)
(b) (2, \(\frac{7}{3}\))
(c) (5, –\(\frac{1}{2}\))
(d) (-6, \(\frac{5}{2}\))
Answer
Answer: (d) (-6, \(\frac{5}{2}\))
Question 17.
A line intersects the y-axis and x-axis at the points P and Q respectively. If (2, -5) is the mid-point of PQ, then the coordinates of P and Q are respectively
(a) (0, -5) and (2, 0)
(b) (0, 10) and (-4, 0)
(c) (0, 4) and (-10, 0)
(d) (0, -10) and (4, 0)
Answer
Answer: (d) (0, -10) and (4, 0)
Question 18.
The area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is
(a) (a + b + c)²
(b) 0
(c) a + b + c
(d) abc
Answer
Answer: (b) 0
Question 19.
If the distance between the points (4, P) and (1, 0) is 5, then the value of P is
(a) 4 only
(b) ± 4
(c) -4 only
(d) 0
Answer
Answer: (b) ± 4
Question 20.
If the points A(1, 2), O(0, 0), C(a, b) are collinear, then
(a) a = b
(b) a = 2b
(c) 2a = b
(d) a = -b
Answer
Answer: (c) 2a = b
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